Examine the data from the EMP table:
EMP_ID DEPT_ID COMMISSION
1 10 500
2 20 1000
3 10
4 10 600
5 30 800
6 30 200
7 10
8 20 300
The COMMISSION column shows the monthly commission earned by the employee. Which three tasks would require subqueries or joins in order to perform in a single step? （）
A. Deleting the records of employees who do not earn commission.
B. Increasing the commission of employee 3 by the average commission earned in department 20.
C. Finding the number of employees who do NOT earn commission and are working for department 20.
D. Inserting into the table a new employee 10 who works for department 20 and earns a commission that is equal to the commission earned by employee 3.
E. Creating a table called COMMISSION that has the same structure and data as the columns EMP_ID and COMMISSIONS of the EMP table.
F. Decreasing the commission by 150 for the employees who are working in department 30 and earning a commission of more then 800.
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A. INSTR returns the numeric position of a named character.
B. NVL2 returns the first non-null expression in the expression list.
C. TRUNCATE rounds the column, expression, or value to n decimal places.
D. DECODE translates an expression after comparing it to each search value.
E. TRIM trims the heading of trailing characters (or both) from a character string.
F. NVL compares two expressions and returns null if they are equal, or the first expression of they are not equal.
G. NULLIF compares twp expressions and returns null if they are equal, or the first expression if they are not equal.
Examine the structure if the EMPLOYEES table:
You need to create a view called EMP_VU that allows the user to insert rows through the view. Which SQL statement, when used to create the EMP_VU view, allows the user to insert rows?（）
A. CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, department_id FROM employees WHERE mgr_id IN (102, 120);
B. CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, job_id department_id FROM employees WHERE mgr_id IN (102, 120);
C. CREATE VIEW emp_Vu AS SELECT department_id, SUM(sal) TOTALSAL FROM employees WHERE mgr_id IN (102, 120) GROUP BY department_id;
D. CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, job_id, DISTINCT department_id FROM employees;
Examine the structure of the STUDENTS table:
STUDENT_ID NUMBER NOT NULL, Primary Key
STUDENT_NAME VARCHAR2(30)
COURSE_ID VARCHAR2(10) NOT NULL
MARKS NUMBER
START_DATE DATE
FINISH_DATE DATE
You need to create a report of the 10 students who achieved the highest ranking in the course INT SQL and who completed the course in the year 1999.
Which SQL statement accomplishes this task?（）
A. SELECT student_ id, marks, ROWNUM "Rank" FROM students WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks DESC;
B. SELECT student_id, marks, ROWID "Rank" FROM students WHERE ROWID <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks;
C. SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks DESC);
D. SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students ORDER BY marks DESC) WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course _ id ='INT _ SQL';
A. CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);
B. CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH READ ONLY;
C. CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH CHECK OPTION;
D. CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);
E. CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) NO UPDATE;
From SQL*Plus, you issue this SELECT statement:
SELECT*
FROM order;
You use this statement to retrieve data from a data table for （）.
A. Updating
B. Viewing
C. Deleting
D. Inserting
E. Truncating
Examine the description of the EMPLOYEES table:
Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only of the minimum salary is less then 5000 and the maximum salary is more than 15000?（）
A. SELECT dept_id, MIN(salary(, MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000;
B. SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000 GROUP BY dept_id;
C. SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) < 5000 AND MAX(salary) > 15000;
D. SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN(salary) < 5000 AND MAX(salary) < 15000;
E. SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN(salary) < 5000 AND MAX(salary) > 15000;
Evaluate this SQL statement:
SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE
FROM employees e, sales s
WHERE e.employee_id = s.emp_id;
What will happen if you remove all the parentheses from the calculation?（）
A. The value displayed in the CALC_VALUE column will be lower.
B. The value displayed in the CALC_VALUE column will be higher.
C. There will be no difference in the value displayed in the CALC_VALUE column.
D. An error will be reported.
The CUSTOMERS table has these columns:
CUSTOMER_ID NUMBER(4) NOT NULL
CUSTOMER_NAME VARCHAR2(100) NOT NULL
STREET_ADDRESS VARCHAR2(150)
CITY_ADDRESS VARCHAR2(50)
STATE_ADDRESS VARCHAR2(50)
PROVINCE_ADDRESS VARCHAR2(50)
COUNTRY_ADDRESS VARCHAR2(50)
POSTAL_CODE VARCHAR2(12)
CUSTOMER_PHONE VARCHAR2(20)
Which statement finds the rows in the CUSTOMERS table that do not have a postal code?（）
A. SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;
B. SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';
C. SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;
D. SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;
E. SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
A. SELECT TO_DATE(SYSDATE, 'FMDAY, DD Month, YYYY') FROM dual;
B. SELECT TO_CHAR(SYSDATE, 'FMDD, DY Month, 'YYYY') FROM dual;
C. SELECT TO_CHAR(SYSDATE, 'FMDay, DD Month, YYYY') FROM dual;
D. SELECT TO_CHAR(SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;
E. SELECT TO_DATE(SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;
最新试题
The PRODUCTS table has these columns:PRODUCT_ID NUMBER(4)PRODUCT_NAME VARCHAR2(45)PRICE NUMBER(8,2)Evaluate this SQL statement:SELECT *FROM PRODUCTSORDER BY price, product _ name;What is true about the SQL statement? （）
What is true about sequences? （）
Which constraint can be defined only at the column level? （）
You need to design a student registration database that contains several tables storing academic information.The STUDENTS table stores information about a student. The STUDENT_GRADES table storesinformation about the student's grades. Both of the tables have a column named STUDENT_ID. The STUDENT_ID column in the STUDENTS table is a primary key.You need to create a foreign key on the STUDENT_ID column of the STUDENT_GRADES table thatpoints to the STUDENT_ID column of the STUDENTS table. Which statement creates the foreign key?（）
Which is a valid CREATE TABLE statement? （）
Which three statements about subqueries are true? （）
Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary KeyFIRST_NAME VARCHAR2(25)LAST_NAME VARCHAR2(25)HIRE_DATE DATEWhich INSERT statement is valid? （）
Which are /SQL*Plus commands? （）
Which object privileges can be granted on a view? （）
For which action can you use the TO_DATE function? （）